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5x^2-57x+148=0
a = 5; b = -57; c = +148;
Δ = b2-4ac
Δ = -572-4·5·148
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-17}{2*5}=\frac{40}{10} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+17}{2*5}=\frac{74}{10} =7+2/5 $
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